Question

Один велосипедист в течении 10 секунд двигался со скоростью= 6 м/с , а второй проехал тот же участок пути за 8 секунд.Найдите среднюю скорость второго велосипедиста

Answer 1

S=V1t1     S=10*6=60 м
60=V2t2     V2=60/8=7.5 м/с

Answer 2

Calculation of Average Speed

To find the average speed of the second cyclist, we need to know the distance traveled by both cyclists. Since the time taken by both cyclists is different, we can calculate the distance traveled by each cyclist using the formula:

Distance = Speed × Time

Let's calculate the distance traveled by the first cyclist:

Distance of the first cyclist = Speed × Time = 6 m/s × 10 s = 60 meters

Now, let's calculate the distance traveled by the second cyclist:

Distance of the second cyclist = Speed × Time = ? × 8 s

Since we don't know the speed of the second cyclist, we need to find it using the distance traveled by the first cyclist.

We can use the formula:

Average Speed = Total Distance ÷ Total Time

The total distance traveled by both cyclists is the same, so we can write:

Total Distance = Distance of the first cyclist = 60 meters

The total time taken by both cyclists is the sum of their individual times:

Total Time = 10 s + 8 s = 18 s

Now, let's substitute the values into the formula to find the average speed of the second cyclist:

Average Speed of the second cyclist = Total Distance ÷ Total Time = 60 meters ÷ 18 s

To calculate the average speed, we need to convert the time from seconds to meters per second.

Let's calculate the average speed:

Average Speed of the second cyclist = 60 meters ÷ 18 s = 3.33 m/s

Therefore, the average speed of the second cyclist is 3.33 m/s.