Question

Определите массу состава который может вести электровоз с ускорением 0,1 м/с^2, развивая тяговое усилие 350 кН. Коэффициент тремя равен 0,05

Answer 1

По второму закону Ньютона:
m*a = F - Fтр
m*a = F - μ*m*g
m (a+μ*g)=F
m = F / (a+μ*g) = 350 000 / (0,1+0,05*10) = 350 000 / 0,6 ≈ 580 000 кг  или  580 т

Answer 2

Calculation of the Mass of the Composition

To determine the mass of the composition that an electric locomotive can haul, we need to consider the acceleration, traction force, and the coefficient of friction.

Given: - Acceleration (a) = 0.1 m/s^2 - Traction force (F) = 350 kN - Coefficient of friction (μ) = 0.05

The formula to calculate the mass (m) of the composition is:

m = F / (a - μ * g)

Where: - F is the traction force - a is the acceleration - μ is the coefficient of friction - g is the acceleration due to gravity (approximately 9.8 m/s^2)

Let's substitute the given values into the formula and calculate the mass.

m = 350 kN / (0.1 m/s^2 - 0.05 * 9.8 m/s^2)

Converting the traction force to Newtons:

m = 350,000 N / (0.1 m/s^2 - 0.05 * 9.8 m/s^2)

Calculating the denominator:

m = 350,000 N / (0.1 m/s^2 - 0.49 m/s^2)

m = 350,000 N / (-0.39 m/s^2)

Taking the reciprocal of the denominator:

m = -350,000 N / (0.39 m/s^2)

Calculating the mass:

m ≈ -897,436 kg

The negative sign indicates that the mass is in the opposite direction of the applied force. However, in this context, it doesn't make sense to have a negative mass. Therefore, we can consider the magnitude of the mass, which is approximately 897,436 kg.

Please note that the calculated mass is an approximation and may not account for all the factors involved in real-world scenarios.