Question

С помощью неподвижного блока поднимают груз массой 50 кг, прикладывая силу 600H.Какой КПД этого блока?

Answer 1

Подвижный блок не даёт выигрыш в силе

КПД = А(п)/А(с) * 100%

А(п) = mgh

A(c) = Fh

КПД = 50кг * 10 * h/ 600 H * h * 100%

Уничтожаем h, получим КПД = 500/600 * 100% ≈ 83% 

Ответ: КПД блока ≈ 83%

Answer 2

Calculation of Efficiency (КПД) of the Block

To calculate the efficiency (КПД) of the block, we need to know the input power and the output power of the block.

The input power (P_in) can be calculated using the formula:

P_in = F × d

Where: - P_in is the input power, - F is the force applied to lift the load (600 N in this case), - d is the distance over which the force is applied.

The output power (P_out) can be calculated using the formula:

P_out = W × v

Where: - P_out is the output power, - W is the weight of the load (50 kg in this case), - v is the velocity at which the load is lifted.

However, the given information does not provide the distance over which the force is applied or the velocity at which the load is lifted. Therefore, it is not possible to calculate the exact efficiency (КПД) of the block without this additional information.

If you can provide the distance or the velocity, I would be able to calculate the efficiency (КПД) for you.