Question

Судно, погруженное в пресную воду до ватерлинии, вытесняет воду объемом 15000 м ^3. вес судна без груза равен 5 * 10^6 Н. чему равен вес груза?

Answer 1

Вес жидкости, вытесненной плавающим телом, равен весу тела в воздухе. Плотность пресной воды ρ=1000 кг/м^3. Масса судна с грузом m1=ρ*V;  m1=15*10^6 кг. Вес судна с грузом P1=150*10^6 Н. 
Вес груза равен P=150*10^6 - 5*10^6 = 145Н

Answer 2

Calculation of Weight of Cargo in a Freshwater-Submerged Ship

To calculate the weight of the cargo in the freshwater-submerged ship, we can use the principle of buoyancy. The weight of the water displaced by the ship is equal to the weight of the ship and its cargo. Given that the ship displaces 15000 m^3 of water and the weight of the ship without cargo is 5 * 10^6 N, we can calculate the weight of the cargo.

Using the principle of buoyancy, the weight of the water displaced by the ship is equal to the weight of the ship and its cargo. Therefore, the weight of the water displaced is 15000 m^3 * 1000 kg/m^3 * 9.81 m/s^2, which is equal to 147,150,000 N.

The weight of the ship without cargo is 5 * 10^6 N.

To find the weight of the cargo, we can subtract the weight of the ship without cargo from the total weight of the ship and its cargo: Weight of cargo = Weight of ship and cargo - Weight of ship without cargo Weight of cargo = 147,150,000 N - 5 * 10^6 N Weight of cargo = 142,150,000 N

Therefore, the weight of the cargo in the freshwater-submerged ship is 142,150,000 N.