Question

Дано:начальная скорость =0.Время изменений скорости=15сек.Конечная скорость=100м/с. Найти:С каким ускорением двигался самолет и какова ее длина?

Answer 1

а=v-V0 разделить на t

a=100м/c-0м/c разделить на 15 с=6,6м/с2 

Answer 2

Given Information:

- Initial velocity (u) = 0 m/s - Time of velocity change = 15 seconds - Final velocity (v) = 100 m/s

Finding Acceleration:

To find the acceleration (a) of the airplane, we can use the following kinematic equation: v = u + at Where: - v = final velocity - u = initial velocity - a = acceleration - t = time

By rearranging the equation to solve for acceleration (a), we get: a = (v - u) / t

Substitute the given values: a = (100 m/s - 0 m/s) / 15 s a = 100 m/s / 15 s a = 6.67 m/s^2

So, the acceleration of the airplane is 6.67 m/s^2.

Finding Distance Traveled:

To find the distance traveled by the airplane, we can use the following kinematic equation: s = ut + (1/2)at^2 Where: - s = distance - u = initial velocity - t = time - a = acceleration

Given that the initial velocity (u) is 0 m/s, the equation simplifies to: s = (1/2)at^2

Substitute the given values: s = (1/2) * 6.67 m/s^2 * (15 s)^2 s = (1/2) * 6.67 m/s^2 * 225 s^2 s = 750 m

So, the length of the path traveled by the airplane is 750 meters.