
Медное жало паяльника массой 59 г остывает от 432°С до 232°С.40% теплоты, выделяющейся при этом,
полезно используется на плавление олова.определите, какую массу олова, взятого при температуре плавления, можно расплавить за счет этой теплоты?

Ответы на вопрос




Calculation of the Mass of Lead that can be Melted
To determine the mass of lead that can be melted using the heat released during the cooling of a copper soldering iron tip, we can use the formula:
Q = mcΔT
Where: - Q is the heat released during the cooling process - m is the mass of the copper soldering iron tip - c is the specific heat capacity of copper - ΔT is the change in temperature
Given the following information: - Mass of the copper soldering iron tip (m) = 59 g - Initial temperature (T1) = 432°C - Final temperature (T2) = 232°C - Percentage of heat used for melting lead = 40%
First, we need to calculate the heat released during the cooling process (Q). We can use the formula:
Q = mcΔT
The specific heat capacity of copper (c) is not provided in the question, so we will assume it to be the average value of 0.39 J/g°C.
Using the given values, we can calculate the heat released during the cooling process:
Q = (59 g) * (0.39 J/g°C) * (432°C - 232°C)
Now, we need to determine the mass of lead that can be melted using 40% of the heat released (Q) during the cooling process.
Let's calculate the mass of lead (m_lead) using the formula:
m_lead = (Q * 0.40) / heat of fusion of lead
The heat of fusion of lead is the amount of heat required to melt one gram of lead, which is approximately 24.5 J/g.
Using the calculated value of Q, we can determine the mass of lead that can be melted:
m_lead = (Q * 0.40) / 24.5 g
Now, let's perform the calculations:
Q = (59 g) * (0.39 J/g°C) * (432°C - 232°C) = 1371.9 J
m_lead = (1371.9 J * 0.40) / 24.5 g ≈ 22.43 g
Therefore, the mass of lead that can be melted at its melting temperature using the heat released during the cooling of the copper soldering iron tip is approximately 22.43 grams.
Please note that the specific heat capacity of copper and the heat of fusion of lead were assumed values for the purpose of this calculation.


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