Question

Тело свободно падает с выстоы h0 = 25м без ачальной скорости как показано на рисунке на какой высоте оно будет через 1с

Answer 1

H=h0-g*t^2/2=25-10*1^2/2=20 м

Answer 2

Calculation of the Height after 1 Second

To calculate the height of an object after 1 second of free fall, we can use the equation of motion for free fall:

h = h0 + v0t + (1/2)gt^2

Where: - h is the final height - h0 is the initial height (given as 25m in this case) - v0 is the initial velocity (which is 0 m/s since the object is dropped without any initial velocity) - t is the time (1 second in this case) - g is the acceleration due to gravity (approximately 9.8 m/s^2)

Plugging in the values into the equation, we get:

h = 25 + 0(1) + (1/2)(9.8)(1)^2

Simplifying the equation, we find:

h = 25 + 0 + 4.9 = 29.9 meters

Therefore, the object will be at a height of approximately 29.9 meters after 1 second of free fall.