
Три резистора сопротивлением R1=2 Ом,R2 = 2.5 Ом и R3 = 3 Ом соединены последовательно в
электрическую цепь.определите напряжение всей цепи,если напряжение на резисторе R2 равно 6В.

Ответы на вопрос

найдем общее сопротивление R= R1+R2+R3 = 2+2,5+3= 7,5 ом
найдем силу тока на втором I2= U2 / R2= 6 / 2,5= 2,4 A
тк соединение последовательное , то ток одинаковый I2= I3= I1 = I
U= I * R = 2,4* 7,5= `18 B



Calculation of the Total Resistance
To determine the voltage across the entire circuit, we first need to calculate the total resistance of the circuit. In this case, the resistors R1, R2, and R3 are connected in series, which means that the total resistance (R_total) is the sum of the individual resistances.The given resistances are: - R1 = 2 Ω - R2 = 2.5 Ω - R3 = 3 Ω
To find the total resistance, we add these values together:
R_total = R1 + R2 + R3
Substituting the given values, we get:
R_total = 2 Ω + 2.5 Ω + 3 Ω
Calculating the sum, we find:
R_total = 7.5 Ω
Calculation of the Total Voltage
Now that we have the total resistance of the circuit, we can calculate the total voltage (V_total) using Ohm's Law. Ohm's Law states that the voltage (V) across a resistor is equal to the current (I) flowing through it multiplied by its resistance (R).In this case, we are given the voltage across resistor R2, which is 6 V. Since the resistors are connected in series, the current flowing through each resistor is the same.
Using Ohm's Law, we can calculate the current (I) flowing through the circuit:
V2 = I * R2
Substituting the given values, we have:
6 V = I * 2.5 Ω
Solving for the current (I), we find:
I = 6 V / 2.5 Ω
Calculating the current, we get:
I ≈ 2.4 A
Now that we have the current, we can calculate the total voltage (V_total) using Ohm's Law:
V_total = I * R_total
Substituting the values we have:
V_total = 2.4 A * 7.5 Ω
Calculating the total voltage, we find:
V_total ≈ 18 V
Answer
Therefore, the voltage across the entire circuit is approximately 18 V.

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