Question

Газ занимает объем 200л при температуре 310К и давлении 50кПа. В процессе изобарного расширения газ проделал работу 1кДж. Найдите конечную температуру газа.

Answer 1

Изобарное расширение=>р=const=p1=p2

A=p*дельтаV=>дельтаV=V2-V1 = A/p = 1000/50000= 0.02 м^3

V1=200л=0,2 м^3

V2=дельтаV+V1 = 0.02+0.2 = 0.22м^3

Тк р=const, то V1/T1 = V2/T2 => T2= (T1*V2) / V1 = (310*0.22) / 0.2 = 341 К

Ответ: Т2 = 341 К

Answer 2

Calculation of Final Temperature

To find the final temperature of the gas, we can use the ideal gas law equation:

PV = nRT

Where: - P is the pressure of the gas - V is the volume of the gas - n is the number of moles of the gas - R is the ideal gas constant - T is the temperature of the gas

Since the process is isobaric (constant pressure), the pressure remains the same. Therefore, we can rewrite the equation as:

V1/T1 = V2/T2

Where: - V1 is the initial volume of the gas - T1 is the initial temperature of the gas - V2 is the final volume of the gas - T2 is the final temperature of the gas

Given: - Initial volume (V1) = 200 L - Initial temperature (T1) = 310 K - Pressure (P) = 50 kPa - Work done (W) = 1 kJ

We need to find the final temperature (T2).