Question

Сколько энергии выделилось при охлаждении куска меди массой 0,6 кг от 272 до 22градуса?

Answer 1

Дано
m=0.6 кг
t1=272 C
t2=22 C
c =400 Дж/кг*С удельная теплоемкость меди
найти
Q - ?
решение
Q = cm(t2-t1) = 400*0.6 (22-272) = - 60000 Дж = - 60 кДж
ОТВЕТ 60 кДж
*** знак минус , так как идет охлаждение - медь ОТДАЕТ тепло

Answer 2

Calculation of Energy Released during Cooling of Copper

To calculate the energy released during the cooling of a copper piece, we can use the formula:

Q = mcΔT

Where: - Q is the energy released or absorbed (in joules) - m is the mass of the copper piece (in kilograms) - c is the specific heat capacity of copper (in joules per kilogram per degree Celsius) - ΔT is the change in temperature (in degrees Celsius)

Given: - Mass of the copper piece (m) = 0.6 kg - Initial temperature (t1) = 272 degrees Celsius - Final temperature (t2) = 22 degrees Celsius

We need to find the energy released (Q).

To calculate the specific heat capacity of copper (c), we can use the value of 400 J/kg°C.

Substituting the given values into the formula, we have:

Q = mcΔT = (0.6 kg)(400 J/kg°C)(22°C - 272°C)

Calculating the change in temperature:

ΔT = t2 - t1 = 22°C - 272°C = -250°C

Substituting the values into the formula:

Q = (0.6 kg)(400 J/kg°C)(-250°C) = -60,000 J

Therefore, the energy released during the cooling of the copper piece with a mass of 0.6 kg from 272°C to 22°C is -60,000 joules.

Please note that the negative sign indicates that energy is released during the cooling process.