Question

Ребят помогите решить задачку пж надо чтобы было дано решение и все полностью прошу очень нужно.Тело массой 3 кг поднимают тросом с ускорением 1 м/с². Определите работу силы натяжения троса в течение первых 10 с движения. .В ответах 1650 Дж

Answer 1

F=m*(g+a)=3*11=33 Н
S=a*t^2/2=1*100/2=50 м
А=F*S=33*50=1650 Дж
Ответ A=1650 Дж

Answer 2

Problem Analysis

We are given the following information: - Mass of the body: 3 kg - Acceleration: 1 m/s² - Time: 10 s

We need to determine the work done by the tension force during the first 10 seconds of motion.

Solution

To solve this problem, we can use the formula for work:

Work = Force × Distance

In this case, the force is the tension force and the distance is the displacement of the body. We can calculate the displacement using the formula:

Displacement = Initial velocity × Time + (1/2) × Acceleration × Time²

Since the body is being lifted vertically, the initial velocity is zero.

Let's calculate the displacement first:

Displacement = 0 × 10 + (1/2) × 1 × (10)² = 0 + 0.5 × 1 × 100 = 50 meters

Now, we can calculate the work done by the tension force:

Work = Force × Distance

The force can be calculated using Newton's second law:

Force = Mass × Acceleration

Force = 3 kg × 1 m/s² = 3 N

Work = 3 N × 50 m = 150 J

Therefore, the work done by the tension force during the first 10 seconds of motion is 150 Joules.

Answer

The work done by the tension force during the first 10 seconds of motion is 150 Joules.