Question

1. определите напряженность электрического поля точечного заряда 0,1 нКл на расстоянии 10 см от него

Answer 1

Е=k*q/r^2

E=9*10^9 * 0.1 * 10⁻⁹ / (0.1 * 10⁻²)² = 90 * 10⁴  H/Кл

Answer 2

Determining the Electric Field Intensity of a Point Charge

To determine the electric field intensity of a point charge, we can use Coulomb's law. Coulomb's law states that the electric field intensity at a point in space due to a point charge is directly proportional to the magnitude of the charge and inversely proportional to the square of the distance from the charge.

In this case, we have a point charge of 0.1 nC (nanocoulombs) located at a distance of 10 cm from the point where we want to determine the electric field intensity.

Using Coulomb's law, we can calculate the electric field intensity as follows:

Step 1: Convert the charge from nanocoulombs to coulombs. 1 nC is equal to 1 × 10^(-9) C.

0.1 nC = 0.1 × 10^(-9) C = 1 × 10^(-10) C

Step 2: Convert the distance from centimeters to meters. 1 cm is equal to 0.01 m.

10 cm = 10 × 0.01 m = 0.1 m

Step 3: Calculate the electric field intensity using Coulomb's law:

Electric field intensity (E) = (k * Q) / r^2

Where: - k is the electrostatic constant, approximately equal to 9 × 10^9 Nm^2/C^2 - Q is the magnitude of the charge - r is the distance from the charge

Substituting the values into the formula:

E = (9 × 10^9 Nm^2/C^2 * 1 × 10^(-10) C) / (0.1 m)^2

Simplifying the equation:

E = (9 × 10^9 Nm^2/C^2 * 1 × 10^(-10) C) / 0.01 m^2

E = 9 × 10^9 Nm^2/C^2 * 1 × 10^(-10) C / 0.01 m^2

E = 9 × 10^9 N * 1 × 10^(-10) / 0.01

E = 9 × 10^(-1) N/C

Therefore, the electric field intensity of the point charge of 0.1 nC at a distance of 10 cm from it is 9 × 10^(-1) N/C.