Question

Помогите решить задачу по физике пожалуйста! ККД ідеального теплового двигуна 40%. Газ одержав від нагрівача 5кДж теплоти. Яка кількість теплоти віддана холодильнику?

Answer 1

Идеальные тепловые двигатели работают по циклу Карно. Для них есть вот такая хорошая формула
n = (Qн - Qх)/Qн = 1 - Qх/Qн = 0.4
Qх/Qн = 1 - 0.4 = 0.6
Qх = Qн * 0.6 = 5*10^3 * 6*10^-1 = 30*10^2 = 3000 Дж

Answer 2

Calculation of Heat Transfer in an Ideal Heat Engine

To solve this problem, we need to use the concept of thermal efficiency (η) of an ideal heat engine. The thermal efficiency is defined as the ratio of the useful work output to the heat input. In this case, the thermal efficiency is given as 40% or 0.4.

The formula for thermal efficiency is:

η = (Useful work output) / (Heat input)

In this problem, the heat input is given as 5 kJ. We need to find the heat output or the amount of heat transferred to the refrigerator.

To find the heat output, we can rearrange the formula as follows:

Heat output = Heat input - Useful work output

Since the thermal efficiency is given as 40%, the useful work output can be calculated as:

Useful work output = Thermal efficiency * Heat input

Substituting the given values:

Useful work output = 0.4 * 5 kJ

Now, we can calculate the useful work output:

Useful work output = 2 kJ

Finally, we can find the heat output by subtracting the useful work output from the heat input:

Heat output = Heat input - Useful work output

Heat output = 5 kJ - 2 kJ

Heat output = 3 kJ

Therefore, the amount of heat transferred to the refrigerator is 3 kJ.

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