Question

Який об'єм займає газ при температурі 77°С, якщо при 27°С його об'єм становив 6 л при сталому тиску?

Answer 1

T1=77+273=350 K, T2= 27+273= 300K, V2= 6 л, p-const. V1-?
 Розвязування.
 При р-const маємо: V1/V2=T1/T2, V1=T1V2/T2, V1= 350*6/300 = 7 л.

Answer 2

Calculation of Gas Volume at Different Temperatures

To calculate the volume of gas at a different temperature, we can use the ideal gas law equation, which states that the product of pressure (P), volume (V), and temperature (T) is constant:

PV = nRT

Where: - P is the pressure of the gas - V is the volume of the gas - n is the number of moles of gas - R is the ideal gas constant (8.314 J/(mol·K)) - T is the temperature of the gas in Kelvin

To solve for the volume of gas at a different temperature, we can rearrange the equation as follows:

V2 = (V1 * T2) / T1

Where: - V1 is the initial volume of the gas - T1 is the initial temperature of the gas in Kelvin - T2 is the final temperature of the gas in Kelvin - V2 is the final volume of the gas

In this case, we are given the initial volume of the gas (V1 = 6 L) at a temperature of 27°C (300 K) and asked to find the final volume of the gas (V2) at a temperature of 77°C (350 K).

Using the formula above, we can calculate the final volume of the gas:

V2 = (6 * 350) / 300 = 7 L

Therefore, the gas would occupy a volume of 7 liters at a temperature of 77°C, assuming the pressure remains constant.

Please note that the calculation assumes ideal gas behavior and a constant pressure.