Question

Мяч бросили вертикально вверх с начальной скоростью 8,0 м\с.Какой максимальной высоты достигнет мяч?

Answer 1

Ek = Eп
mv^2/2 = mgh
h = v^2/2g = 8^2/2*10 = 3.2 м

Answer 2

В верхней точке тело останавливается V=0
V= V0-gt
0= 8- 10t
t= 0,8 c -время подъема
Высота подъема H= V0t - gt^2/2
H= 8*0,8 - 10*0,64/ 2= 6,4 - 3,2= 3,2 м

Answer 3

Calculation of the maximum height reached by the ball

To calculate the maximum height reached by the ball, we can use the equations of motion. The initial velocity of the ball is given as 8.0 m/s.

Using the equation h = V₀t - (1/2)gt², where: - h is the maximum height reached by the ball, - V₀ is the initial velocity of the ball, - t is the time taken to reach the maximum height, - g is the acceleration due to gravity (approximately 9.8 m/s²),

we can substitute the given values into the equation to find the maximum height.

Let's calculate it step by step:

1. Calculate the time taken to reach the maximum height: - We know that the initial velocity of the ball is 8.0 m/s. - Since the ball is thrown vertically upwards, the final velocity at the maximum height is 0 m/s. - Using the equation V = V₀ - gt, we can solve for t: 0 = 8.0 - 9.8t t = 8.0 / 9.8 t ≈ 0.82 s

2. Substitute the calculated time into the equation to find the maximum height: - Using the equation h = V₀t - (1/2)gt², we can substitute the values: h = (8.0)(0.82) - (1/2)(9.8)(0.82)² h ≈ 3.27 m

Therefore, the maximum height reached by the ball is approximately 3.27 meters.