Question

Массасы 100 кг дене 10 м биіктіктен биіктігі 3 м үйдің төбесіне құлап түсті.Ауырлық күшінің істеген жұмысы қандай?

Answer 1

M=100кг
h=10м
h=3м
A=?
A=F×S S=h
F=mg
g=10Н/кг
F=100кг×10Н/кг=1000Н
A=1000Н×10м=10000Дж
А=1000Н×3м=3000Дж

Answer 2

The question is about the work done by the gravitational force on a body of mass 100 kg that falls from a height of 10 m to a roof of height 3 m. The answer is that the work done by the gravitational force is equal to the change in the potential energy of the body, which is given by the formula:

$$W = mg(h_1 - h_2)$$

where $m$ is the mass of the body, $g$ is the acceleration due to gravity, and $h_1$ and $h_2$ are the initial and final heights of the body, respectively. Plugging in the given values, we get:

$$W = 100 \times 10 \times (10 - 3) = 7000 \text{ J}$$

The work done by the gravitational force is 7000 J, which means that the body loses 7000 J of potential energy as it falls. This is a basic concept of physics that you can learn more about from various sources, such as [this one](https://surak.baribar.kz/457616/). I hope this helps you understand the problem better.