
начав движение из состояния покоя с ускорением 6 м/с^2тело достигает скорости 36 м/с, движется
дальше с этой скоростью и останавливается через 5 с. Какой путь прошло тело за все время движения

Ответы на вопрос

Разобьём движение на промежутки
1) сначало тело ускорялось с нулевой скоростью
2) замедлялось и остановилось
т.е
S=at1^2/2+vot3+at3^2/2=
=6*6*6/2+36*5-36*5/2=198 метров



a=6m/c2 36/6=6c
v=36v/c 6+5=11c
t=5c 36*11=396m
s-?



Calculation of Distance Traveled
To calculate the distance traveled by the object, we need to determine the time it takes for the object to reach its final velocity and then come to a stop.
Given: - Initial velocity (u) = 0 m/s (since the object starts from rest) - Acceleration (a) = 6 m/s^2 - Final velocity (v) = 36 m/s - Time taken to reach final velocity (t1) = ? - Time taken to come to a stop (t2) = 5 s
To find the time taken to reach the final velocity (t1), we can use the equation:
v = u + at
Substituting the given values:
36 = 0 + 6t1
Solving for t1:
t1 = 36 / 6 = 6 s
So, it takes 6 seconds for the object to reach its final velocity.
Now, to find the distance traveled during this time, we can use the equation:
s = ut + (1/2)at^2
Substituting the values:
s1 = 0 * 6 + (1/2) * 6 * (6)^2 = 0 + 18 * 36 = 648 m
Therefore, the distance traveled during the time it takes to reach the final velocity is 648 meters.
Next, we need to find the distance traveled during the time it takes for the object to come to a stop (t2 = 5 s). Since the object is moving at a constant velocity of 36 m/s during this time, the distance traveled can be calculated using the equation:
s = vt
Substituting the values:
s2 = 36 * 5 = 180 m
Therefore, the distance traveled during the time it takes for the object to come to a stop is 180 meters.
Finally, to find the total distance traveled by the object, we add the distances traveled during the two time intervals:
Total distance = s1 + s2 = 648 + 180 = 828 meters
Therefore, the object traveled a total distance of 828 meters during its entire motion.


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