Question

Темпнратура латунной детали массой 0,2кг равна 365°С.Какое количество теплоты она передаст окружающим телам,охлаждаясь до температуры 15°С? заранее спасибо

Answer 1

Удельная теплоемкость латуни: с = 380 Дж/кг*К
Количество отданной теплоты: Q = c*m*(t1-t2) = 380 * 0,2* 350 = 26600 Дж.
Ответ: 26,6 кДж. 

Answer 2

Calculation of Heat Transfer

To calculate the amount of heat transferred by a brass object cooling from 365°C to 15°C, we can use the formula:

Q = mcΔT

Where: - Q is the amount of heat transferred - m is the mass of the object - c is the specific heat capacity of the material - ΔT is the change in temperature

In this case, the mass of the brass object is given as 0.2 kg, and the temperature change is from 365°C to 15°C.

Now, we need to find the specific heat capacity of brass. Unfortunately, the search results did not provide a specific value for the specific heat capacity of brass. However, we can assume a rough estimate based on the specific heat capacity of copper, which is similar to brass. The specific heat capacity of copper is approximately 0.385 J/g°C.

Converting the mass of the brass object from grams to kilograms, we have:

m = 0.2 kg

The change in temperature is:

ΔT = (365°C - 15°C) = 350°C

Now, we can calculate the amount of heat transferred using the formula:

Q = mcΔT

Substituting the values:

Q = (0.2 kg) * (0.385 J/g°C) * (350°C)

Calculating the result:

Q ≈ 27.95 kJ

Therefore, the brass object will transfer approximately 27.95 kJ of heat to the surroundings as it cools from 365°C to 15°C.

Please note that the specific heat capacity of brass may vary depending on the specific composition of the alloy. The value used in this calculation is an estimate based on the specific heat capacity of copper.