Question

Помогите,мне на завтра нужно 1.Під дією якої сили стальний брусок буде рухатись рівномірно по льоду? Маса бруска 16 кг,коефіцієнт тертя 0,02 2.Яка сила тяги вантажу масою 260 кг,якщо він за 4с змінив швидкість з 4м/с до 6м/с

Answer 1

1. F+Fтр = 0, значит F=-Fтр. Найдем силу трения:
Fтр=мN; N=-mg=-16кг × 10 м/с² = -160Н.
Fтр= 0,02 × (-160Н) = -3,2Н, следовательно F=3,2Н

2. Сначала ищем ускорение по формуле
a = (V-Vo) / t = (6м/с - 4м/с)/10с = 0,2 м/с²
Затем, по 2 закону Ньютона:
F=ma=0,2 м/с² × 260 кг = 52Н

Answer 2

Forces Affecting the Motion of a Steel Block on Ice

When a steel block is placed on ice, several forces come into play that affect its motion. The main forces to consider are the gravitational force (weight), the normal force, and the force of friction.

The gravitational force, also known as weight, is the force exerted on an object due to gravity. It is given by the formula:

Weight = mass x acceleration due to gravity

In this case, the mass of the steel block is given as 16 kg. The acceleration due to gravity is approximately 9.8 m/s^2. Therefore, the weight of the steel block can be calculated as:

Weight = 16 kg x 9.8 m/s^2

To determine the force required for the steel block to move uniformly on ice, we need to consider the force of friction. The force of friction opposes the motion of an object and is influenced by the coefficient of friction and the normal force.

The normal force is the force exerted by a surface to support the weight of an object resting on it. On a horizontal surface, the normal force is equal in magnitude and opposite in direction to the weight of the object.

The force of friction can be calculated using the formula:

Force of friction = coefficient of friction x normal force

In this case, the coefficient of friction is given as 0.02. To calculate the normal force, we can use the weight of the steel block. Therefore, the force of friction can be calculated as:

Force of friction = 0.02 x (16 kg x 9.8 m/s^2)

Calculation of the Force of Traction

To calculate the force of traction, we need to use the equation:

Force of traction = mass x change in velocity / time

In this case, the mass of the load is given as 260 kg. The change in velocity is the difference between the final velocity and the initial velocity. The time taken for this change is given as 4 seconds.

The change in velocity can be calculated as:

Change in velocity = final velocity - initial velocity

Substituting the given values, we have:

Change in velocity = 6 m/s - 4 m/s

Now, we can calculate the force of traction using the formula:

Force of traction = 260 kg x (6 m/s - 4 m/s) / 4 s

Answer:

1. The steel block will move uniformly on ice under the influence of the force of friction. The force of friction is determined by the coefficient of friction and the normal force. The force required for the steel block to move uniformly can be calculated as 0.02 times the weight of the block [[1]].

2. The force of traction required to change the velocity of a load from 4 m/s to 6 m/s in 4 seconds can be calculated using the formula mentioned above. Substituting the given values, the force of traction is determined to be 260 kg x (6 m/s - 4 m/s) / 4 s [[2]].

Please note that the calculations provided are based on the given information and assumptions.