Question

СРОЧНООО С помощью неподвижного блока равномерно подняли груз массой 45 кг на высоту 3 м. каков КПД блока, если приложенная сила была равна 500Н? есть ли в условии лишние данные?

Answer 1

Кпд=m*g*h*100%/F*h=45*10/500=90%
Да: высота.

Answer 2

Calculation of Efficiency (КПД) of the Block

To calculate the efficiency (КПД) of the block, we can use the formula:

Efficiency (КПД) = (Useful work output / Total work input) x 100%

In this case, the useful work output is the work done in lifting the load, and the total work input is the work done by the applied force.

The useful work output can be calculated using the formula:

Useful work output = Force x Distance

Given that the force applied is 500 N and the distance lifted is 3 m, we can calculate the useful work output:

Useful work output = 500 N x 3 m = 1500 Nm

The total work input can be calculated using the formula:

Total work input = Force x Distance

Since the force applied is 500 N and the distance lifted is 3 m, the total work input is:

Total work input = 500 N x 3 m = 1500 Nm

Now, we can substitute the values into the efficiency formula:

Efficiency (КПД) = (1500 Nm / 1500 Nm) x 100% = 100%

Therefore, the efficiency (КПД) of the block is 100%.

Analysis of the Given Data

The given data includes the mass of the load (45 kg) and the applied force (500 N). These values are necessary for calculating the efficiency of the block. There are no extra or unnecessary data provided in the given information.

Please let me know if there is anything else I can help you with.