Question

Для охлаждения лимонада в него бросили 4 кубика льда при температуре 0 ºС. Масса каждого кубика 8 г. Первоначальная температура лимонада 30 ºС. Какова масса лимонада в стакане, если в конце процесса установилась температура 15ºC? Тепловыми потерями пренебречь. Удельная теплоёмкость лимонада такая же, как у воды. Ответ представить в единицах СИ.

Answer 1

N=4    
m=8*10^-3 кг
  t1=30  
 t2=15  
t3=0  
λ=3.3*10^5 Дж/кг
   c=4200 Дж/кг*С  М=?__________________

c*M*(t1-t2)=λ*n*m+c*n*m*(t2-t3)лед растает и  нагреется M=n*m*(λ+c*(t2-t3))/(c*t1-t2))=4*8*10^-3*(3.3*10^5+4200*15)/(4200*15)=0.2 кг

Answer 2

Problem Analysis

We are given the following information: - 4 ice cubes, each with a mass of 8 g, are added to a glass of lemonade. - The initial temperature of the lemonade is 30ºC. - The ice cubes are at a temperature of 0ºC. - The final temperature of the lemonade is 15ºC. - We can neglect any heat losses during the process. - The specific heat capacity of the lemonade is the same as that of water.

We need to determine the mass of the lemonade in the glass.

Solution

To solve this problem, we can use the principle of conservation of energy. The heat lost by the lemonade as it cools down is equal to the heat gained by the ice cubes as they melt.

The heat lost by the lemonade can be calculated using the formula:

Q_lost = m_lemonade * c * (T_initial - T_final)

Where: - Q_lost is the heat lost by the lemonade - m_lemonade is the mass of the lemonade - c is the specific heat capacity of the lemonade (which is the same as that of water) - T_initial is the initial temperature of the lemonade - T_final is the final temperature of the lemonade

The heat gained by the ice cubes can be calculated using the formula:

Q_gained = m_ice * L_f

Where: - Q_gained is the heat gained by the ice cubes - m_ice is the mass of the ice cubes - L_f is the latent heat of fusion of ice, which is 334 J/g

Since the heat lost by the lemonade is equal to the heat gained by the ice cubes, we can set up the following equation:

m_lemonade * c * (T_initial - T_final) = m_ice * L_f

We can rearrange this equation to solve for the mass of the lemonade:

m_lemonade = (m_ice * L_f) / (c * (T_initial - T_final))

Now we can substitute the given values into the equation to find the mass of the lemonade.

Calculation

Given: - m_ice = 4 ice cubes * 8 g/ice cube = 32 g - L_f = 334 J/g - c = specific heat capacity of water = 4.18 J/gºC - T_initial = 30ºC - T_final = 15ºC

Substituting these values into the equation, we get:

m_lemonade = (32 g * 334 J/g) / (4.18 J/gºC * (30ºC - 15ºC))

Simplifying the equation:

m_lemonade = 2672 g / (4.18 J/gºC * 15ºC)

m_lemonade ≈ 40.24 g

Therefore, the mass of the lemonade in the glass is approximately 40.24 grams.

Answer

The mass of the lemonade in the glass is approximately 40.24 grams.