Question

Два резистори опором 6 і 10 Ом ввімкнені в коло послідовно. Яка кількість теплоти виділиться в кожному резисторі за 2 хв, якщо напруга на другому дорівнює 20 В?

Answer 1

I=U2/R2=20/10=2 A
Q1=I^2*R1*t=2^2*6*2*60=2880 Дж
Q2=2^2*R2*t=2^2*10*2*60=4800 Дж

Answer 2

Calculation of Heat Dissipation in Each Resistor

To calculate the amount of heat dissipated in each resistor, we can use the formula:

Q = I^2 * R * t

Where: - Q is the heat dissipated in joules (J) - I is the current flowing through the resistor in amperes (A) - R is the resistance of the resistor in ohms (Ω) - t is the time in seconds (s)

In this case, the resistors are connected in series, which means the current flowing through both resistors will be the same. Let's assume the current flowing through the circuit is I.

For the first resistor with a resistance of 6 Ω, the heat dissipated can be calculated as:

Q1 = I^2 * 6 * 120

For the second resistor with a resistance of 10 Ω and a voltage of 20 V, we can use Ohm's law to calculate the current:

I = V / R = 20 / 10 = 2 A

Now, we can calculate the heat dissipated in the second resistor:

Q2 = I^2 * 10 * 120

Let's calculate the values:

Q1 = (I^2) * 6 * 120

Q2 = (I^2) * 10 * 120

Now, let's substitute the value of I into the equations and calculate the heat dissipated in each resistor.