Question

Алюминиевый брусок размером 10 х 4 х 5 см погружен в керосин на 1/3 своего объема. Чему равна выталкивающая сила,действующая на брусок

Answer 1

10*4*5=200 это у нас размер габаритный выталкивающ сила равна 200* 1/3=67,45=67Па
67/10=6,7=7Н - выталк сила

Answer 2

Calculation of the Buoyant Force

To calculate the buoyant force acting on the aluminum block submerged in kerosene, we need to determine the volume of the block and the density of the kerosene.

The volume of the aluminum block can be calculated using the formula:

Volume = Length x Width x Height

Given that the dimensions of the block are 10 cm x 4 cm x 5 cm, the volume can be calculated as follows:

Volume = 10 cm x 4 cm x 5 cm = 200 cm³.

The block is submerged in kerosene up to 1/3 of its volume. Therefore, the volume of kerosene displaced by the block can be calculated as:

Displaced Volume = Volume of Block x 1/3 = 200 cm³ x 1/3 = 66.67 cm³.

Next, we need to determine the density of kerosene. The density of kerosene can vary slightly depending on the specific type and temperature. However, a commonly used value for the density of kerosene is approximately 0.8 g/cm³.

Now, we can calculate the mass of the kerosene displaced by the block using the formula:

Mass = Density x Volume

Mass = 0.8 g/cm³ x 66.67 cm³ = 53.34 g.

Finally, we can calculate the buoyant force using the formula:

Buoyant Force = Mass x Acceleration due to Gravity

The acceleration due to gravity is approximately 9.8 m/s².

Converting the mass from grams to kilograms:

Mass = 53.34 g = 0.05334 kg.

Calculating the buoyant force:

Buoyant Force = 0.05334 kg x 9.8 m/s² = 0.523 m/s².

Therefore, the buoyant force acting on the aluminum block submerged in kerosene is approximately 0.523 N.

Please note that the above calculations assume ideal conditions and do not take into account factors such as surface tension or the shape of the block.