Question

На пружину действует сила 20 Н, под действием которой она удлиняется на 4 см.Определите ее жесткость.

Answer 1

Fупр=k* дельта x
дельта x-удлинение
k-жесткость
k=F/дельта x
k=20H/ 4 cм= 5 H/см

Answer 2

Calculation of the Spring Constant

To determine the spring constant (also known as stiffness or force constant), we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position.

Hooke's Law can be expressed as:

F = kx

Where: - F is the force applied to the spring (20 N in this case) - k is the spring constant (to be determined) - x is the displacement of the spring (4 cm or 0.04 m in this case)

To find the spring constant, we rearrange the equation:

k = F / x

Substituting the given values:

k = 20 N / 0.04 m

Calculating the result:

k = 500 N/m

Therefore, the spring constant is 500 N/m.