Question

Самосвал,двигаясь под уклон,прошел за 20с. путь 340м. и развил скорость 18м/с.Найдите ускорение самосвала и его скорость в начале уклона.

Answer 1

Так как это равноускоренное движение
$S = \frac{V_{1}+V_{0}}{2}*t\\\\V_{0}=\frac{2S}{t}-V_{1}\\\\V_{0}=\frac{2*340m}{20s}-18m/s\\\\V_{0}=16m/s$

Теперь легко найти ускорение
$a=\frac{V_{1}-V_{0}}{t}\\\\a=\frac{18m/s-16m/s}{20s}=0.1m/s^{2}$

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Answer 2

Given Information:

- Time taken to travel: 20 seconds - Distance traveled: 340 meters - Final velocity: 18 m/s

Calculating Acceleration:

To find the acceleration of the dump truck, we can use the following equation:

Final velocity (v) = Initial velocity (u) + Acceleration (a) * Time (t)

We are given the final velocity (v) as 18 m/s and the time (t) as 20 seconds. We need to find the acceleration (a).

Using the equation, we can rearrange it to solve for acceleration:

a = (v - u) / t

Since the initial velocity (u) is not given, we can assume it to be 0, as the question asks for the speed at the beginning of the slope.

Substituting the values into the equation:

a = (18 m/s - 0 m/s) / 20 s

Simplifying the equation:

a = 18 m/s / 20 s

Calculating the acceleration:

a = 0.9 m/s²

Therefore, the acceleration of the dump truck is 0.9 m/s².

Calculating Initial Velocity:

To find the initial velocity of the dump truck at the beginning of the slope, we can use the following equation:

Final velocity (v) = Initial velocity (u) + Acceleration (a) * Time (t)

We are given the final velocity (v) as 18 m/s, the time (t) as 20 seconds, and the acceleration (a) as 0.9 m/s². We need to find the initial velocity (u).

Using the equation, we can rearrange it to solve for initial velocity:

u = v - a * t

Substituting the values into the equation:

u = 18 m/s - 0.9 m/s² * 20 s

Simplifying the equation:

u = 18 m/s - 18 m/s

Calculating the initial velocity:

u = 0 m/s

Therefore, the initial velocity of the dump truck at the beginning of the slope is 0 m/s.