Question

Автомобиль двигался со скоростью 20м/с, затем происходило торможение с ускарением 4м/с^ найдите пусть пройденного автомобилем за 6 с после момента начала торможения.помог те пожалуйста

Answer 1

Сначала проверим сколько времени потребуется на полную остановку

$v=v0-at$

$0=20-4t$

$t=20/4=5s$через 5 секунд автомобиль остановится

нужно найти путь, пройденный за 6с, 

за 5 остановится и 1 секунду стоит

значит путь пройденный за 6 секунд= пути за 5

$S(5)=v0t- \frac{at ^{2} }{2} =20*5- \frac{4*25}{2} =100-50=50m$ Ответ

Answer 2

Calculation of Distance Traveled

To find the distance traveled by the car during the 6 seconds after the start of braking, we can use the equations of motion. The initial velocity of the car is 20 m/s, and the acceleration during braking is -4 m/s^2 (negative because it is deceleration).

We can use the following equation to calculate the distance traveled:

Distance = Initial Velocity * Time + (1/2) * Acceleration * Time^2

Substituting the given values: Initial Velocity = 20 m/s Acceleration = -4 m/s^2 Time = 6 s

Distance = 20 * 6 + (1/2) * (-4) * 6^2

Simplifying the equation: Distance = 120 - 72 = 48 meters

Therefore, the car will travel a distance of 48 meters during the 6 seconds after the start of braking.

Please note that the above calculation assumes constant acceleration during the entire braking period and does not take into account any other factors that may affect the motion of the car.