Question

на кусок пробки целиком погруженный в воду действует архимедова сила 49 Н.Каков объем пробки?

Answer 1

$F_{a}$=p*g*V

p=1000кг/м^3

g=10

$F_{a}$=49H

$V=\frac{F_{a}}{p*g}$

V=0,0049м^3

 

 

 

 

 

 

 

 

 

 

 

Answer 2

Calculation of the Volume of the Cork

To calculate the volume of the cork, we can use Archimedes' principle, which states that the buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.

Given that the buoyant force acting on the cork is 49 N, we can equate this force to the weight of the fluid displaced by the cork.

Let's assume the density of water is ρ = 1000 kg/m³.

The weight of the fluid displaced by the cork can be calculated using the formula:

Weight of fluid displaced = density of fluid × volume of fluid displaced × acceleration due to gravity

Since the cork is fully submerged in water, the weight of the fluid displaced is equal to the weight of the cork itself, which is 49 N.

We can rearrange the formula to solve for the volume of fluid displaced:

Volume of fluid displaced = weight of fluid displaced / (density of fluid × acceleration due to gravity)

Substituting the given values:

Volume of fluid displaced = 49 N / (1000 kg/m³ × 9.8 m/s²)

Calculating the volume of fluid displaced:

Volume of fluid displaced ≈ 0.005 m³

Therefore, the volume of the cork is approximately 0.005 cubic meters.

Please note that the above calculation assumes that the cork is a perfect solid and does not take into account any irregularities or air pockets in the cork.