Question

Трактор двигаясь равномерно за время t=3.0 мин, проходит путь S=150м. Мощность двигателя ровна N=120kBm.найти силу тяги F?

Answer 1

t=3*60=180 c    s=150 м    N=120*10^3 Вт    F=?

N=F*v=F*s/t       F=N*t/s=120*10^3*180/150=144*10^3 H   (144 кН)

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Answer 2

Calculation of Tractor's Pulling Force

To calculate the pulling force of the tractor, we can use the formula:

Power (P) = Work / Time

Where: - Power (P) is given as 120 kW (kilowatts) or 120,000 W (watts) - Time (t) is given as 3.0 minutes or 180 seconds - Work is the product of force and distance (W = F * S)

First, let's convert the time from minutes to seconds: - t = 3.0 minutes = 3.0 * 60 seconds = 180 seconds

Now, we can calculate the work done by the tractor using the given power and time.

Calculation Steps

1. Convert the power from kilowatts to watts: - Power (P) = 120 kW = 120,000 W

2. Calculate the work done by the tractor: - Work (W) = Power * Time - Work (W) = 120,000 W * 180 s - Work (W) = 21,600,000 J (joules)

3. Use the work formula to find the force (F) exerted by the tractor: - Work (W) = Force (F) * Distance (S) - Force (F) = Work / Distance - Force (F) = 21,600,000 J / 150 m - Force (F) = 144,000 N (newtons)

Result

The pulling force exerted by the tractor is 144,000 N.