Question

Тело падало без начальной скорости с высоты 21,5 м в течение 2,1 с. Найдите ускорение движения тела.

Answer 1

Используем формулу:h=at\2a=2h\ta=2*21.5\4.41=9,75

округляем h=9.8

 

Answer 2

H=at^2\2 выражаем а: a=2h\t^2=43\4.41=9.75

Answer 3

Calculation of Acceleration

To find the acceleration of the falling object, we can use the kinematic equation:

\[h = \frac{1}{2}gt^2\]

Where: - h is the height (21.5 m in this case) - g is the acceleration due to gravity (unknown) - t is the time (2.1 s in this case)

We can rearrange the equation to solve for g:

\[g = \frac{2h}{t^2}\]

Substituting the given values:

\[g = \frac{2 \times 21.5}{2.1^2}\]

Simplifying the equation:

\[g = \frac{43}{4.41}\]

Calculating the value:

\[g \approx 9.75 \, \text{m/s}^2\]

Therefore, the acceleration of the falling object is approximately 9.75 m/s^2.