Question

Груз массой 2 кг упал без начальной скорости с высоты 4 м от пола на стол высотой 1 м,стоящий на полу.Работа силы тяжести при падении груза равноРебята помогите плииз

Answer 1

Дано h1=4 м   h2=1 м     A -  ?

A= m*g*(h1-h2)=2*10*3=60 Дж

Ответ A=60 Дж

Answer 2

Calculation of Work Done by Gravity

To calculate the work done by gravity when the 2 kg mass falls from a height of 4 m onto a table that is 1 m high, we need to consider the change in potential energy.

The potential energy of an object at a certain height is given by the formula:

Potential Energy = mass * gravity * height

In this case, the mass is 2 kg, the height is 4 m, and the acceleration due to gravity is approximately 9.8 m/s^2.

So, the initial potential energy of the mass at a height of 4 m is:

Initial Potential Energy = 2 kg * 9.8 m/s^2 * 4 m

To find the final potential energy of the mass when it reaches the table, we need to consider the height of the table, which is 1 m.

Final Potential Energy = 2 kg * 9.8 m/s^2 * 1 m

The work done by gravity is equal to the change in potential energy, which can be calculated as:

Work Done by Gravity = Final Potential Energy - Initial Potential Energy

Let's calculate the values:

Initial Potential Energy = 2 kg * 9.8 m/s^2 * 4 m = 78.4 Joules

Final Potential Energy = 2 kg * 9.8 m/s^2 * 1 m = 19.6 Joules

Work Done by Gravity = 19.6 Joules - 78.4 Joules = -58.8 Joules

The negative sign indicates that work is done against gravity, as the object is moving in the opposite direction of the gravitational force.

Therefore, the work done by gravity when the 2 kg mass falls from a height of 4 m onto a table that is 1 m high is -58.8 Joules.