Question

Первую половину пути автобус шёл со скоростью в 8 раз большей, чем вторую. Средняя скорость автобуса на всё пути равна 16 км/ч. Определите скорость автобуса на второй половине пути.

Answer 1

(8х+х)/2=16
9х=32
х=32/9=3,56 км/ч

Answer 2

Solution:

Given: - The bus traveled the first half of the distance at a speed 8 times greater than the second half. - The average speed of the bus for the entire journey is 16 km/h.

Let's denote the speed of the bus for the second half of the journey as v.

We can use the formula for average speed: Average Speed = Total Distance / Total Time

The total distance is the same for both halves of the journey, and the total time is the same for both halves of the journey.

The time for the first half of the journey is half the total time, and the time for the second half of the journey is also half the total time.

Calculation:

Let's calculate the speed of the bus for the second half of the journey.

The average speed of the bus for the entire journey is given as 16 km/h. Using this information, we can calculate the speed of the bus for the second half of the journey.

The formula for average speed is: Average Speed = Total Distance / Total Time

We know that the total distance is the same for both halves of the journey, and the total time is the same for both halves of the journey.

Let's denote the total distance as d and the total time as t.

For the first half of the journey: - Speed = 8v - Time = t/2

For the second half of the journey: - Speed = v - Time = t/2

Using the formula for average speed: Average Speed = Total Distance / Total Time

We can write the equation: 16 = d / t

Substituting the distances and times for the first and second halves of the journey, we get: 16 = (8v * t/2 + v * t/2) / t

Solving for v: 16 = (4vt + vt) / t 16 = 5vt / t 16 = 5v

Solving for v: v = 16 / 5 v = 3.2 km/h

Answer:

The speed of the bus for the second half of the journey is 3.2 km/h.