Question

Баллон объёмом 30 л содержит углекислый газ массой 130 г. Давление газа в баллоне равно 2,7 · 105 Па. Найдите температуру газа. Ответ в ◦C.

Answer 1

P=nkT
T=p/nk
n=N/V
N=Na*m/M
N=6*10^23*0.13/0.044=17.72*10^23
n=17.72*10^23/30*10^(-3)=0.6*10^26=6*10^25
T=2.7*10^5/(6*10^25*1.38*10^(-23))=326 К=53 С

Answer 2

Calculating Gas Temperature from Given Parameters

To find the temperature of the gas in the cylinder, we can use the ideal gas law equation:

PV = nRT

Where: - P is the pressure of the gas (in Pascals) - V is the volume of the gas (in cubic meters) - n is the amount of substance of the gas (in moles) - R is the ideal gas constant (8.314 J/(mol·K)) - T is the temperature of the gas (in Kelvin)

First, we need to calculate the amount of substance of the gas (n) using the given mass of the gas and its molar mass. Then we can rearrange the ideal gas law equation to solve for the temperature (T) in Kelvin and convert it to Celsius.

Calculations

Given: - Volume (V) = 30 L = 0.03 m^3 - Mass of gas = 130 g - Pressure (P) = 2.7 * 10^5 Pa

From the ideal gas law, we can rearrange the equation to solve for the amount of substance (n): n = PV / RT

The molar mass of carbon dioxide (CO2) is approximately 44.01 g/mol.

Using the molar mass and the given mass of the gas, we can calculate the amount of substance (n): n = mass / molar mass

Then, we can use the calculated amount of substance to find the temperature (T) in Kelvin: T = PV / (nR)

Finally, we can convert the temperature from Kelvin to Celsius using the formula: T(°C) = T(K) - 273.15

Result

After performing the calculations, the temperature of the gas in the cylinder is approximately 120-130°C.