Question

Чему равен период колебания пружинного маятника если его масса раана200г,а коэффициент упругости пружины равен 2000Нм

Answer 1

T=2*pi*sqrt(m/k)=6,28*sqrt(0,2/2000)=6,28*10^-2 c

Answer 2

Period of a Spring Pendulum

The period of a spring pendulum can be calculated using the formula:

T = 2π√(m/k)

Where: - T = period of oscillation - m = mass of the pendulum - k = spring constant

Calculation

Given: - Mass (m) = 200 g = 0.2 kg - Spring constant (k) = 2000 N/m

Using the formula, we can calculate the period of oscillation:

T = 2π√(m/k) T = 2π√(0.2/2000) T = 2π√(0.0001) T = 2π * 0.01 T = 0.0628 seconds

Therefore, the period of oscillation for the given spring pendulum is approximately 0.0628 seconds.