Question

Какая сила действует на проводник длиной 0.2 м в магнитном поле с индукцией 1.5 тл действует сила 1.5 Н.Какой силы ток протикает в проводнике,если угол между направлениями индукции и тока - 30 градусов

Answer 1

F = J*B*L*sinα.
J = F/(B*L*sinα).
J = 1.5/(1.5*0.2*0.5) = 10 A.

Answer 2

Calculation of the Current in the Conductor

To determine the current flowing through the conductor, we can use the formula for the force acting on a conductor in a magnetic field:

F = B * I * L * sin(θ)

Where: - F is the force acting on the conductor (given as 1.5 N) - B is the magnetic field induction (given as 1.5 T) - I is the current flowing through the conductor (to be determined) - L is the length of the conductor (given as 0.2 m) - θ is the angle between the direction of the magnetic field and the direction of the current (given as -30 degrees)

We can rearrange the formula to solve for the current I:

I = F / (B * L * sin(θ))

Substituting the given values into the formula:

I = 1.5 N / (1.5 T * 0.2 m * sin(-30°))

Before proceeding with the calculation, we need to convert the angle from degrees to radians, as the trigonometric functions in the formula require radians.

Converting -30 degrees to radians:

θ_rad = -30° * (π / 180°) = -π/6 radians

Now we can calculate the current I:

I = 1.5 N / (1.5 T * 0.2 m * sin(-π/6))

To calculate the sine of -π/6, we can use the fact that the sine function is an odd function, which means that sin(-x) = -sin(x). Therefore, sin(-π/6) = -sin(π/6).

I = 1.5 N / (1.5 T * 0.2 m * (-sin(π/6)))

Using a calculator, we find that sin(π/6) is approximately 0.5.

I = 1.5 N / (1.5 T * 0.2 m * (-0.5))

Simplifying the expression:

I = 1.5 N / (-0.15 T * m)

I ≈ -10 A

Therefore, the current flowing through the conductor is approximately -10 A.

Please note that the negative sign indicates that the current is flowing in the opposite direction to the magnetic field.