Question

Чему равна масса гравитационного притяжения между двумя одинаквыми бильярдными шарами в момент столкновения? Масса каждого шара 200 гр, диаметр 4 см

Answer 1

F = G(m1*m2/R^2)

R = 4 см так как расстояние есть 2 радиуса шаров
G — гравитационная константа
m1 m2 — массы.

переводите все в основные единицы и подставляйте.

Answer 2

Gravitational Attraction Between Two Identical Billiard Balls

The gravitational attraction between two objects can be calculated using the formula for gravitational force:

F = G * (m1 * m2) / r^2

Where: - F is the gravitational force - G is the gravitational constant (approximately 6.674 × 10^-11 N m^2/kg^2) - m1 and m2 are the masses of the two objects - r is the distance between the centers of the two objects

In this case, the mass of each billiard ball is 200 grams, and the diameter is 4 cm. To find the gravitational force between the two billiard balls at the moment of collision, we can use the above formula.

Calculation

The mass of each ball is 200 grams, which is equal to 0.2 kg. The distance between the centers of the two balls at the moment of collision can be approximated as the sum of their radii, which is equal to the diameter of one ball.

Given: - m1 = m2 = 0.2 kg - r = 4 cm = 0.04 m

Plugging these values into the formula, we get: F = G * (m1 * m2) / r^2

Result

The gravitational force between the two identical billiard balls at the moment of collision can be calculated using the above formula.

F = G * (0.2 kg * 0.2 kg) / (0.04 m)^2

Let's calculate the result.