Question

Определите вес алюминиевого цилиндра объемом 200 см,подвешенного на прочной нити .к чему приложен вес ?

Answer 1

Вес = Масса * Ускорение свободного падения.

Вес= 2,6989*200$^{10}$.

вес= 5397,8гр*м/с2 или 5,8 Н..

Приложен вес к растягивающейся нити..

Answer 2

Calculating the Weight of an Aluminum Cylinder

To determine the weight of an aluminum cylinder with a volume of 200 cm³ when suspended on a strong thread, we can use the formula:

Weight (W) = Volume (V) × Density (D) × Acceleration due to gravity (g)

Where: - Volume (V) = 200 cm³ - Density (D) = 2.7 g/cm³ (density of aluminum) - Acceleration due to gravity (g) = 9.8 m/s²

Calculation

Using the given formula, we can calculate the weight of the aluminum cylinder:

Weight (W) = Volume (V) × Density (D) × Acceleration due to gravity (g)

Weight (W) = 200 cm³ × 2.7 g/cm³ × 9.8 m/s²

Converting cm³ to m³: 1 cm³ = 1 × 10^-6 m³

So, 200 cm³ = 200 × 10^-6 m³

Now, we can calculate the weight.

Weight (W) = (200 × 10^-6 m³) × 2.7 g/cm³ × 9.8 m/s²

Weight (W) = 0.0002 m³ × 2.7 g/cm³ × 9.8 m/s²

Weight (W) = 0.0002 m³ × 2.7 g/cm³ × 9.8 m/s² = 0.0054 kg

Therefore, the weight of the aluminum cylinder is 0.0054 kg when suspended on a strong thread.