Question

2 тела, масса которых 100г и 150г соединены нитью, перекинутый через невесомый блок. Через 0,5 секунды после начала движения нить обрывается. Найти путь, пройденным вторым телом за 2 секунды после начала движения

Answer 1

Пока тела на блоке, тело 2 движется вниз с ускорением
a=(m2-m1)*g/(m2+m1)
в остальное время ускорение равно g
S=a*t1^2/2+a*t1*(t2-t1)+g*(t2-t1)^2/2=
=(m2-m1)*g/(m2+m1)*t1*(t2-t1/2)+g*(t2-t1)^2/2=
=(0,15-0,1)*10/(0,15+0,1)*0,5*(2-0,5/2)+10*(2-0,5)^2/2 м =13 м

Answer 2

Problem Analysis

We have two bodies with masses of 100g and 150g connected by a string. The string is passed over an weightless block. After 0.5 seconds of motion, the string breaks. We need to find the distance traveled by the second body 2 seconds after the start of the motion.

Solution

To solve this problem, we can use the equations of motion. Let's denote the mass of the first body as m1 (100g) and the mass of the second body as m2 (150g). We are given that the string breaks after 0.5 seconds, so we can calculate the acceleration of the system using the equation:

a = 2 / t^2 where a is the acceleration and t is the time.

Next, we can calculate the distance traveled by the second body using the equation:

s = ut + (1/2)at^2 where s is the distance, u is the initial velocity (which is 0 in this case), a is the acceleration, and t is the time.

Substituting the values into the equation, we get:

s = (1/2)at^2 Now, let's calculate the acceleration using the given time:

a = 2 / (0.5)^2 = 16 m/s^2 Finally, we can calculate the distance traveled by the second body after 2 seconds:

s = (1/2)(16)(2)^2 = 32 meters Therefore, the second body travels a distance of 32 meters after 2 seconds.

Answer

The second body travels a distance of 32 meters after 2 seconds.

Note: The given search results did not provide a direct solution to the problem. However, the equations of motion are well-known and widely used in physics to solve problems related to motion.