Question

3)определить емкость конденсаторов (паралельное соединение)если C1=C2=C3=4МКФ,С4=20МКФ 2)емкости двух конденсаторов 4 и 6 мкф.какова их общая емкость при последовательном соединении?

Answer 1

3) при параллельном соединении C=C1+C2+C3+C4=3*C1+C4=12+20=32 мкФ

2) для последовательного соединения
1/C=1/C1+1/C2=1/4+1/6=3/12 +2/12=5/12

C=12/5=2,4 мкФ

Answer 2

Capacitance of Capacitors in Parallel

When capacitors are connected in parallel, the total capacitance is the sum of the individual capacitances. In this case, if C1, C2, and C3 are all 4μF, and C4 is 20μF, the total capacitance when they are connected in parallel can be calculated as follows:

Total capacitance in parallel = C1 + C2 + C3 + C4

Substituting the given values:

Total capacitance in parallel = 4μF + 4μF + 4μF + 20μF

Total capacitance in parallel = 32μF

Therefore, the total capacitance when the capacitors C1, C2, C3, and C4 are connected in parallel is 32μF.

Capacitance of Capacitors in Series

When capacitors are connected in series, the reciprocal of the total capacitance is equal to the sum of the reciprocals of the individual capacitances. In this case, if the capacitances of two capacitors are 4μF and 6μF, the total capacitance when they are connected in series can be calculated as follows:

Total capacitance in series = 1 / (1/C1 + 1/C2)

Substituting the given values:

Total capacitance in series = 1 / (1/4μF + 1/6μF)

Simplifying the expression:

Total capacitance in series = 1 / (3/12μF + 2/12μF)

Total capacitance in series = 1 / (5/12μF)

Total capacitance in series = 12μF / 5

Therefore, the total capacitance when the capacitors with capacitances of 4μF and 6μF are connected in series is 12/5μF or 2.4μF.

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