Question

Стальная пружина под действием силы 120 н удлинилась на 15 мм.Найдите её жесткость

Answer 1

Из закона Гука F=k*x
k=F/x=120/0,015=8000 Н/м

Answer 2

Calculation of the Spring Constant

To find the spring constant (also known as the stiffness or force constant) of a steel spring, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position.

Hooke's Law can be expressed as:

F = k * x

Where: - F is the force applied to the spring (in newtons, N) - k is the spring constant (in newtons per meter, N/m) - x is the displacement of the spring (in meters, m)

In this case, we are given that the spring elongates by 15 mm (or 0.015 m) under the influence of a force of 120 N. We can use this information to calculate the spring constant.

F = 120 N x = 0.015 m

Using Hooke's Law, we can rearrange the equation to solve for the spring constant:

k = F / x

Substituting the given values:

k = 120 N / 0.015 m

Calculating the result:

k = 8000 N/m

Therefore, the spring constant of the steel spring is 8000 N/m.