Question

На сколько градусов охладится 40 г льда, если он при этом отдает количество теплоты 500 дж?

Answer 1

Дано:
m=40 г
Q=500 Дж
с=2100 Дж/ (кг * градус Цельсия)
Найти:
дельта t
СИ:
40 г = 0,04 кг
Решение:
Q=c*m*дельта t
дельта t = Q/cm
Вычисления:
дельта t = 500 Дж / (2100 Дж/кг* гр. Цельсия * 0,04 кг) = 6 гр. Цельсия
Ответ: дельта t = 6 гр. Цельсия

Answer 2

Calculating the Cooling of Ice

To calculate the change in temperature when a certain amount of heat is removed from a substance, we can use the formula:

Q = mcΔT

Where: - Q = amount of heat transferred - m = mass of the substance - c = specific heat capacity of the substance - ΔT = change in temperature

In this case, we are given: - Q = 500 J (amount of heat transferred) - m = 40 g (mass of ice) - c = specific heat capacity of ice

We need to calculate the change in temperature (ΔT) when 500 J of heat is removed from 40 g of ice.

Calculation

Using the formula Q = mcΔT, we can rearrange it to solve for ΔT: ΔT = Q / (mc)

The specific heat capacity of ice is approximately 2.09 J/g°C.

Substitute the given values into the formula: ΔT = 500 J / (40 g * 2.09 J/g°C)

Calculating the value: ΔT ≈ 500 J / 83.6 J/°C ≈ 5.98°C

So, the ice will cool by approximately 5.98°C when 500 J of heat is removed.

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