Question

Брусок равномерно тянут силой 4Н .Чему равен коэфициент трения между бруском и столом ,если масса бруска 2 кг

Answer 1

Fтрен=Мю[N]
Fтрен=Мюmg 
Мю=Fтрен/mg=4/2*10=0.2
вроде так)

Answer 2

Calculation of the Coefficient of Friction

To calculate the coefficient of friction between the block and the table, we need to use the formula:

Coefficient of Friction (μ) = Force of Friction (F) / Normal Force (N)

Given that the block is being pulled with a force of 4 N and has a mass of 2 kg, we can calculate the normal force using the formula:

Normal Force (N) = mass (m) * acceleration due to gravity (g)

Let's calculate the normal force first:

Normal Force (N) = 2 kg * 9.8 m/s^2 = 19.6 N Now, we can calculate the coefficient of friction:

Coefficient of Friction (μ) = Force of Friction (F) / Normal Force (N) = 4 N / 19.6 N ≈ 0.2041

Therefore, the coefficient of friction between the block and the table is approximately 0.2041.

Please note that the coefficient of friction can vary depending on the surface properties of the block and the table, as well as other factors such as the presence of lubricants or surface roughness.