Question

Самосвал при перевозке груза развивает мощность 25 кВт. Какая работа (в МДж) совершается силой тяги самосвала за 4 мин? В ответ запишите только численное значение работы в мегаджоулях без указания единиц измерения. (6000 не подошло)

Answer 1

дано:           cи

N=25кВт=25000Вт

t=4мин=240с

A-?

  решение:

А=N*T=25000Вт*240с=6МДж=6000000

ответ A=6МДж=6000000        

Answer 2

Calculation of Work Done by the Dump Truck

To calculate the work done by the dump truck, we need to know the power and the time it takes to perform the task. In this case, the power of the dump truck is given as 25 kW, and the time taken is 4 minutes.

The formula to calculate work is:

Work = Power × Time

Let's substitute the given values into the formula:

Work = 25 kW × 4 minutes

To calculate the work in megajoules (MJ), we need to convert kilowatts (kW) to megajoules (MJ).

According to the conversion factor, 1 kilowatt-hour (kWh) is equal to 3.6 megajoules (MJ). Therefore, 1 kilowatt (kW) is equal to 3.6 kilojoules (kJ).

Let's convert kilowatts (kW) to megajoules (MJ):

25 kW × 3.6 MJ/kW = 90 MJ

Therefore, the work done by the dump truck is 90 megajoules (MJ).