Question

Сопротивление лампочки накаливания в рабочем состоянии 240 Ом. Напряжение в сети 120 В. Сколько ламп включено параллельно в сеть, если мощность, потребляемая всеми лампочками, равна 600 Вт?

Answer 1

P=IU=U²/R=U²/(R/n)=nU²/R
n=PR/U²=600*240/120²=10 применяем законы параллельного соединения проводников

Answer 2

Calculation of the Number of Light Bulbs in Parallel

To determine the number of light bulbs connected in parallel to the network, we need to use the formula for calculating the total resistance in a parallel circuit. In a parallel circuit, the total resistance is given by the reciprocal of the sum of the reciprocals of the individual resistances.

The formula for calculating the total resistance in a parallel circuit is:

1/R_total = 1/R1 + 1/R2 + 1/R3 + ...

In this case, the resistance of each light bulb is given as 240 Ω, and the voltage in the network is 120 V. The power consumed by all the light bulbs is given as 600 W.

To find the number of light bulbs, we can rearrange the formula for power:

P = V^2 / R

Where: - P is the power consumed by all the light bulbs (600 W) - V is the voltage in the network (120 V) - R is the resistance of each light bulb (240 Ω)

Substituting the given values into the formula, we can solve for the number of light bulbs:

600 = 120^2 / (240 * n)

Where n is the number of light bulbs.

Simplifying the equation:

600 = 120^2 / (240 * n)

600 = 14400 / (240 * n)

600 = 60 / n

Cross-multiplying:

600n = 60

Dividing both sides by 600:

n = 60 / 600

n = 0.1

Therefore, the number of light bulbs connected in parallel to the network is 0.1. However, since we cannot have a fraction of a light bulb, we can conclude that there is either 0 or 1 light bulb connected in parallel to the network.

Please note that the calculation assumes that the resistance of each light bulb remains constant and that the light bulbs are identical.