Question

Какая масса никеля выделится на поверхности изделия с площадью 120 см^2 в процессе электролиза при толщине покрытия 0,03мм?

Answer 1

Дано:
S=120 см²=120·10⁻⁴ м²
h = 0,03 мм = 0,03·10⁻³ м
ρ = 8900 кг/м³ - плотность никеля
_____________
m - ?

m = ρ·V = ρ·S·h = 8900·120·10⁻⁴·0,03·10⁻³=0,0032  кг = 3,2 г

Answer 2

Calculation of Nickel Mass

To calculate the mass of nickel that will be deposited on the surface of the object during electrolysis, we need to use the formula:

Mass = Density x Volume

In this case, the density of nickel is not provided, so we will assume a typical value of 8.908 grams per cubic centimeter (g/cm³) for nickel.

The volume of the deposited nickel can be calculated using the formula:

Volume = Area x Thickness

Given: - Area = 120 cm² - Thickness = 0.03 mm = 0.003 cm

Let's calculate the mass of nickel:

Volume = 120 cm² x 0.003 cm = 0.36 cm³

Mass = 0.36 cm³ x 8.908 g/cm³ = 3.20288 grams

Therefore, approximately 3.20288 grams of nickel will be deposited on the surface of the object during electrolysis.

Please note that the density of nickel may vary slightly depending on the specific alloy or impurities present. The assumed value of 8.908 g/cm³ is an average value commonly used for pure nickel.