Question

Определите энергию фотона, длина волны которого равна Лямбда=4*10^-7м.

Answer 1

E=h*c/L=6,62*10^-34*3*10^8/4*10^-7=4,97*10^-19 Дж

Answer 2

Energy of a Photon with Wavelength λ=4*10^-7m

The energy of a photon can be determined using the equation:

E = hc/λ

Where: - E = energy of the photon - h = Planck's constant (6.626 x 10^-34 J·s) - c = speed of light in a vacuum (3.00 x 10^8 m/s) - λ = wavelength of the photon

Substituting the given value of λ=4*10^-7m into the equation:

E = (6.626 x 10^-34 J·s * 3.00 x 10^8 m/s) / (4*10^-7m)

E = (1.9878 x 10^-25 J·m) / (4*10^-7m)

E ≈ 4.97 x 10^-19 J

Therefore, the energy of a photon with a wavelength of λ=4*10^-7m is approximately 4.97 x 10^-19 joules.