Question

Скорость точек рабочей поверхности наждачного круга диаметром 300мм равна 35м.с чему равен период обращения наждачного круга??

Answer 1

Ω = 2π/Т ⇒ Т = 2π/ω           (1)
V = ωR ⇒ ω = V/R
Подставить значение ω в (1) ⇒ Т = 2πR/V = (2·3,14·0,3)/35 = 0.054 сек.

Answer 2

V=омега*R
омега=2*π/T
v=(2*π/T)*R
v=(2*π/T)*d/2
v=2*π*d/2*T
T=π*d/v
T=3.14*0.3/3.5=0.269c

Answer 3

Calculation of the Period of Rotation of the Sanding Wheel

To calculate the period of rotation of the sanding wheel, we need to know the speed of the points on the working surface of the wheel and the diameter of the wheel.

Given: - Speed of the points on the working surface of the sanding wheel: 35 m/s - Diameter of the sanding wheel: 300 mm

To calculate the period of rotation, we can use the formula:

Period = Circumference / Speed

The circumference of the sanding wheel can be calculated using the formula:

Circumference = π * Diameter

Substituting the given values:

Circumference = π * 300 mm

Converting the diameter from millimeters to meters:

Circumference = π * 0.3 m

Now, we can calculate the period of rotation:

Period = (π * 0.3 m) / 35 m/s

Calculating the value:

Period ≈ 0.0085 s

Therefore, the period of rotation of the sanding wheel is approximately 0.0085 seconds.

Please note that the above calculation assumes that the speed of the points on the working surface of the sanding wheel is constant and does not take into account any other factors that may affect the actual period of rotation.