Question

Сколько тепла выделится при кристаллизации 5 литров воды, азятой при 0 граддусоов цельсия?

Answer 1

5 литров это 5 кг воды   Q=лямбда*m=330000*5=1650000 Дж

Answer 2

Calculating Heat Released During Crystallization of Water

To calculate the heat released during the crystallization of 5 liters of water at 0 degrees Celsius, we can use the formula:

Q = m * L

Where: - Q = heat released (in joules) - m = mass of the substance undergoing phase change (in kilograms) - L = latent heat of fusion for the substance (in joules per kilogram)

Mass of Water

The mass of 5 liters of water can be calculated using the density of water, which is approximately 1000 kg/m³.

m = V * ρ Where: - m = mass - V = volume - ρ = density

Calculating the mass: m = 5 L * 1000 kg/m³ = 5000 kg

Latent Heat of Fusion of Water

The latent heat of fusion of water is approximately 334,000 joules per kilogram.

Calculation

Using the given values: Q = 5000 kg * 334,000 J/kg = 1,670,000,000 joules

Therefore, approximately 1,670,000,000 joules of heat will be released during the crystallization of 5 liters of water at 0 degrees Celsius.