Question

Три потребителя сопротивлением 20, 40 и 24 Ом соединены параллельно. Напряжение на концах этого участка цепи 24 В. Определитель силу тока в каждом потребителе, общую силу тока в участке цепи и сопротивление участка цепи.

Answer 1

U1=U2=U3=U=24
По закону Ома I=U/R
I1=U/R1=24/24=1A
I2=U/R2=40/24~1,6666A
I3=U/R3=20/24~0,8333A

Answer 2

Calculation of Current and Resistance in the Circuit

To determine the current and resistance in the circuit, we need to consider the three consumers connected in parallel with resistances of 20 Ω, 40 Ω, and 24 Ω, respectively. The voltage across this section of the circuit is given as 24 V.

To find the current flowing through each consumer, we can use Ohm's Law, which states that the current (I) flowing through a resistor is equal to the voltage (V) across the resistor divided by its resistance (R). Mathematically, this can be expressed as:

I = V / R

Let's calculate the current in each consumer:

1. For the consumer with a resistance of 20 Ω: - Current (I1) = Voltage (V) / Resistance (R1) = 24 V / 20 Ω = 1.2 A

2. For the consumer with a resistance of 40 Ω: - Current (I2) = Voltage (V) / Resistance (R2) = 24 V / 40 Ω = 0.6 A

3. For the consumer with a resistance of 24 Ω: - Current (I3) = Voltage (V) / Resistance (R3) = 24 V / 24 Ω = 1 A

Now, let's calculate the total current flowing through the circuit. Since the consumers are connected in parallel, the total current is the sum of the individual currents:

Total Current (Itotal) = I1 + I2 + I3

Substituting the values we calculated earlier:

Itotal = 1.2 A + 0.6 A + 1 A = 2.8 A

Finally, let's calculate the equivalent resistance of the circuit. In a parallel circuit, the reciprocal of the equivalent resistance is equal to the sum of the reciprocals of the individual resistances:

1/Req = 1/R1 + 1/R2 + 1/R3

Substituting the resistance values:

1/Req = 1/20 Ω + 1/40 Ω + 1/24 Ω

Simplifying the equation:

1/Req = 0.05 + 0.025 + 0.04167

1/Req = 0.11667

Taking the reciprocal of both sides:

Req = 1 / 0.11667 ≈ 8.57 Ω

Therefore, the total resistance of the circuit is approximately 8.57 Ω.

Summary of Results:

- The current flowing through the consumer with a resistance of 20 Ω is approximately 1.2 A. - The current flowing through the consumer with a resistance of 40 Ω is approximately 0.6 A. - The current flowing through the consumer with a resistance of 24 Ω is approximately 1 A. - The total current flowing through the circuit is approximately 2.8 A. - The equivalent resistance of the circuit is approximately 8.57 Ω.

Please note that the calculations provided above are based on the given information and assumptions.