Question

Тепловой двигатель совершил полезную работу 30 Дж, и израсходовал при этом 2,5 киллограма бензина. Найти КПД теплового двигателя.​

Answer 1

Дано:
А пол = 30 Дж
m = 2,5 кг
q = 46 * 10**6 Дж
Найти:
КПД
Решение:
КПД = А пол/Q, Q= qm
КПД = А пол/ qm

Answer 2

Calculation of Thermal Efficiency

To find the thermal efficiency (η) of a heat engine, we can use the formula:

η = (Useful work output) / (Energy input)

In this case, the useful work output is given as 30 J, and the energy input is the amount of gasoline consumed, which is 2.5 kg.

Let's calculate the thermal efficiency:

η = (30 J) / (2.5 kg)

To proceed with the calculation, we need to convert the mass of gasoline from kilograms to joules. We can use the energy density of gasoline, which is approximately 32 MJ/kg.

Energy input = (2.5 kg) * (32 MJ/kg)

Now we can substitute the values into the formula:

η = (30 J) / [(2.5 kg) * (32 MJ/kg)]

Let's calculate the thermal efficiency using the given values:

η = (30 J) / [(2.5 kg) * (32 MJ/kg)]

Calculating the thermal efficiency:

η ≈ 0.000375

Therefore, the thermal efficiency of the heat engine is approximately 0.000375, or 0.0375%.

Please note that the given information does not specify the type of heat engine or provide additional details. The calculation assumes a simplified scenario and uses the given values to determine the thermal efficiency.