Question

1.Какова сила упругости, возникающая в пружине, жесткостью 100 Н/м, если она растянулась на 2,5см?​

Answer 1

Ответ:

2,5H

Объяснение:

$F_{y} = kx\\F_{y} = 100*0,025\\F_{y} = 2,5 H$

Answer 2

Calculating the Spring Force

To calculate the spring force, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position.

Given: - Spring stiffness (k) = 100 N/m - Displacement (x) = 2.5 cm = 0.025 m

Using Hooke's Law, the spring force (F) can be calculated using the formula: F = kx

Substituting the given values: F = 100 N/m * 0.025 m

F = 2.5 N

Therefore, the spring force exerted when the spring is stretched by 2.5 cm is 2.5 N.